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output: expose output_apply_state() to header

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- need a way to apply the work of commit without side-effects
- related to 8f67446cc7 and f042de3f51
This commit is contained in:
EBADBEEF 2023-08-23 15:02:02 -07:00
parent 7431d840d0
commit a1ddc25b45
2 changed files with 2 additions and 1 deletions
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1
include/types/wlr_output.h
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@ -28,6 +28,7 @@ void output_defer_present(struct wlr_output *output, struct wlr_output_event_pre
bool output_prepare_commit(struct wlr_output *output, const struct wlr_output_state *state);
void output_apply_commit(struct wlr_output *output, const struct wlr_output_state *state);
void output_send_commit_event(struct wlr_output *output, const struct wlr_output_state *state);
void output_apply_state(struct wlr_output *output, const struct wlr_output_state *state);
void output_state_get_buffer_src_box(const struct wlr_output_state *state,
struct wlr_fbox *out);

2
types/output/output.c
View file

@ -210,7 +210,7 @@ void wlr_output_set_description(struct wlr_output *output, const char *desc) {
wl_signal_emit_mutable(&output->events.description, output);
}
static void output_apply_state(struct wlr_output *output,
void output_apply_state(struct wlr_output *output,
const struct wlr_output_state *state) {
if (state->committed & WLR_OUTPUT_STATE_RENDER_FORMAT) {
output->render_format = state->render_format;