sink-input, source-output: Don't assume that proplist has been initialized in free()

It's bad form to assume in free() that any member of the struct has
been initialized. I ran into problems with this when I reordered
things in pa_sink_input_new() and pa_source_output_new().
This commit is contained in:
Tanu Kaskinen 2013-11-13 17:38:56 +02:00
parent 94c4034426
commit c88a703441
2 changed files with 4 additions and 2 deletions

View file

@ -781,7 +781,8 @@ static void sink_input_free(pa_object *o) {
if (PA_SINK_INPUT_IS_LINKED(i->state))
pa_sink_input_unlink(i);
pa_log_info("Freeing input %u \"%s\"", i->index, pa_strnull(pa_proplist_gets(i->proplist, PA_PROP_MEDIA_NAME)));
pa_log_info("Freeing input %u \"%s\"", i->index,
i->proplist ? pa_strnull(pa_proplist_gets(i->proplist, PA_PROP_MEDIA_NAME)) : "");
/* Side note: this function must be able to destruct properly any
* kind of sink input in any state, even those which are

View file

@ -667,7 +667,8 @@ static void source_output_free(pa_object* mo) {
if (PA_SOURCE_OUTPUT_IS_LINKED(o->state))
pa_source_output_unlink(o);
pa_log_info("Freeing output %u \"%s\"", o->index, pa_strnull(pa_proplist_gets(o->proplist, PA_PROP_MEDIA_NAME)));
pa_log_info("Freeing output %u \"%s\"", o->index,
o->proplist ? pa_strnull(pa_proplist_gets(o->proplist, PA_PROP_MEDIA_NAME)) : "");
if (o->node)
pa_node_free(o->node);