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	aupdate: implicitly call _write_swap() if it wasn't called explicitly
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					 2 changed files with 12 additions and 0 deletions
				
			
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			@ -39,6 +39,7 @@ struct pa_aupdate {
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    pa_atomic_t read_lock;
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    pa_mutex *write_lock;
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    pa_semaphore *semaphore;
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    pa_bool_t swapped;
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};
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pa_aupdate *pa_aupdate_new(void) {
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			@ -101,6 +102,8 @@ unsigned pa_aupdate_write_begin(pa_aupdate *a) {
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    n = (unsigned) pa_atomic_load(&a->read_lock);
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    a->swapped = FALSE;
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    return !WHICH(n);
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}
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			@ -119,11 +122,16 @@ unsigned pa_aupdate_write_swap(pa_aupdate *a) {
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            break;
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    }
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    a->swapped = TRUE;
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    return WHICH(n);
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}
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void pa_aupdate_write_end(pa_aupdate *a) {
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    pa_assert(a);
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    if (!a->swapped)
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        pa_aupdate_write_swap(a);
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    pa_mutex_unlock(a->write_lock);
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}
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			@ -93,6 +93,10 @@ unsigned pa_aupdate_write_swap(pa_aupdate *a);
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 *    pa_update_write_end(a)
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 * }
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 *
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 * In some cases keeping both structures up-to-date might not be
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 * necessary, since they are fully rebuilt on each iteration
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 * anyway. In that case you may leave the _write_swap() call out, it
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 * will then be done implicitly in the _write_end() invocation.
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 */
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#endif
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