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92f0815e4d
We delay the audio a bit to keep packet intervals equal, which keeps some data in buffers. In theory the calculation keeps one buffer free, but it doesn't explicitly keep "extra" buffer space so in theory might flush too late and next process() might not have free buffers. However, as we encode next packet right away this shouldn't really occur... Try to keep one extra spare buffer free so that the flush time is certainly early enough. |
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