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handle read from timerfd correctly

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When reading the timerfd gives an error, we should return right away
because the timeout did not happen.

If we change the timerfd timeout before reading it, we can get -EAGAIN.
Don't log an error in that case but wait for the new timeout.
This commit is contained in:
Wim Taymans 2022-12-09 17:30:31 +01:00
parent 3a443b4e1c
commit f44d55f6c2
14 changed files with 153 additions and 55 deletions
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15
spa/plugins/vulkan/vulkan-compute-source.c
View file

@ -267,14 +267,20 @@ static void set_timer(struct impl *this, bool enabled)
}
}
static void read_timer(struct impl *this)
static int read_timer(struct impl *this)
{
uint64_t expirations;
int res = 0;
if (this->async || this->props.live) {
if (spa_system_timerfd_read(this->data_system, this->timer_source.fd, &expirations) < 0)
perror("read timerfd");
if ((res = spa_system_timerfd_read(this->data_system,
this->timer_source.fd, &expirations)) < 0) {
if (res != -EAGAIN)
spa_log_error(this->log, NAME " %p: timerfd error: %s",
this, spa_strerror(res));
}
}
return res;
}
static int make_buffer(struct impl *this)
@ -284,7 +290,8 @@ static int make_buffer(struct impl *this)
uint32_t n_bytes;
int res;
read_timer(this);
if (read_timer(this) < 0)
return 0;
if ((res = spa_vulkan_ready(&this->state)) < 0) {
res = SPA_STATUS_OK;