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audioconvert: somewhat avoid precision loss in S32 to F32 conversion
At the very least, we should go through s25_32 intermediate instead of s24_32, to avoid needlessly loosing 1 LSB precision bit. That being said, i suspect it's still not doing the right thing. Why are we silently dropping those 7 LSB bits? Is that really the way to do it?
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parent
175d533b56
commit
c517865864
4 changed files with 38 additions and 46 deletions
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@ -335,7 +335,7 @@ conv_s32_to_f32d_1s_sse2(void *data, void * SPA_RESTRICT dst[], const void * SPA
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float *d0 = dst[0];
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uint32_t n, unrolled;
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__m128i in;
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__m128 out, factor = _mm_set1_ps(1.0f / S24_SCALE);
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__m128 out, factor = _mm_set1_ps(1.0f / S25_SCALE);
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if (SPA_IS_ALIGNED(d0, 16))
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unrolled = n_samples & ~3;
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@ -347,14 +347,14 @@ conv_s32_to_f32d_1s_sse2(void *data, void * SPA_RESTRICT dst[], const void * SPA
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s[1*n_channels],
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s[2*n_channels],
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s[3*n_channels]);
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in = _mm_srai_epi32(in, 8);
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in = _mm_srai_epi32(in, 7);
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out = _mm_cvtepi32_ps(in);
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out = _mm_mul_ps(out, factor);
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_mm_store_ps(&d0[n], out);
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s += 4*n_channels;
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}
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for(; n < n_samples; n++) {
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out = _mm_cvtsi32_ss(factor, s[0]>>8);
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out = _mm_cvtsi32_ss(factor, s[0]>>7);
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out = _mm_mul_ss(out, factor);
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_mm_store_ss(&d0[n], out);
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s += n_channels;
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